find the reminder when p(x)=x cube - 6x square+2x-4 is divided by q(x)=1-2x
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Hi Vaibhavi Akshita, P(x) = x^3 - 6 x^2 + 2 x - 4
Divisor is 1 - 2 x
Equating 1- 2 x = 0 you get x = 1/2
So required remainder is got from P(1/2)
===> (1/2)^3 - 6 (1/2)^2 + 2 (1/2) - 4
==> 1/8 - 6/4 + 1 - 4 = (1 -12 - 24) / 8 = -35/8
Divisor is 1 - 2 x
Equating 1- 2 x = 0 you get x = 1/2
So required remainder is got from P(1/2)
===> (1/2)^3 - 6 (1/2)^2 + 2 (1/2) - 4
==> 1/8 - 6/4 + 1 - 4 = (1 -12 - 24) / 8 = -35/8
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