Math, asked by bhavana568, 6 months ago

Find the reminder when x^3-8 divided by (x-2)​

Answers

Answered by vedakamatshankhwalka
1

Answer:

0 is the remainder

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Answered by bnida0392
1

Answer:

Hence,

x-2=0

Then,

x=2

Now According to remainder theorem ,

By putting the value of X in the given equation (x^3-8)

we get,

=2^3-8

= 8-8

=0

Hence,

The remainder is equal to 0.

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Hope you understand.........

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