find the reminder when x cube +3x square +3x+1 is divided by x -1 /2
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using remainder theorem
x=1/2
x^3+3x^2+3x+1
=(1/2)^3+3(1/2)^2+3 (1/2)+1
=1/8+3/4+3/2+1
=1+6+9+8/8
=24/8
=3
so the remainder is 3
x=1/2
x^3+3x^2+3x+1
=(1/2)^3+3(1/2)^2+3 (1/2)+1
=1/8+3/4+3/2+1
=1+6+9+8/8
=24/8
=3
so the remainder is 3
appu79:
txs for the helping hand
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