Question

find the reminder when X3 + 3x2 + 3x + 1 is divided by x + 1

Answer 1

x+1=0

x=-1

x^3+3x^2+3x+1

-1^3+3×-1^2+3×-1+1

-1+3-3+1

0

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Answer 2

Given :-

$\sf{x}^{3} + 3 {x}^{2} + 3x + 1$

$\sf\:x + 1 = 0$

$x = 0 - 1$

$x = - 1$

To :-

Find the remainder of the above expression

Solution :-

$\sf( { - 1})^{3} + 3({ - 1})^{2} + 3( - 1) + 1$

$\sf- 1 + 3 - 3 + 1$

$\sf0 \: Ans$

Procedure :-

→ This question is from the polynomials.

→ Here we will first find yeh zero of x - 1 and then the zero will be -1.

→ Then we will put -1 in place of X and then we will equate the whole expression.

→ I have put +3 because if there will be any number with negetive sign we we have to do square of it that number will be converted into positive sign. Just like that -1 will be converted into +1 and then we will multiple it with 3 and rest of the number with the -1.

→ After that -1 and +1 will get cancelled and +3 and -3 will also get cancelled hence, the final answer will be 0

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