Question

find the reminder when x³-ax²+6x-a is divided by x - a​

Answer 1

Answer:

5a

Step-by-step explanation:

See

let P(x)=x³-ax²+6x-a

So it will be done using remainder theorem

as x-a=0

so x=a

put this value of a in p(x)

(a)³-a(a)²+6(a)-a

=a³-a³+6a-a

=5a

I hope it helps

Answer 2

Answer:

let p(x)=

$x {}^{2} - ax {}^{2} + 6x - a$

x-a=0

x=a

let's put the value of x that is -a in p(x)

now, it will become

$( a) {}^{3} - a( a) {}^{2} + 6(a) - a$

$= a {}^{3} - a {}^{3} + 6a - a$

$= 5a$

Step-by-step explanation:

hope it will help you

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