Find the required amount of IBA chemical required to prepare 250 ppm in 200 ml
of solvent.?
Answer it in sum model.
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Answer:
Explanation:Solve for volume. 10,000 ppm X Vol (ml) = 250 ppm X 1000 ml.
Divide both sides by 10,000 ppm. Vol (ml) = 250 ppm X 1000 ml / 10,000 ppm.
Multiply 250 ppm by 1000 ml. ...
Divide by 10,000 ppm. ...
Add 25 ml of concentrate to 1
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