Question

Find the required diameter of steel rod that has to carry an axial pull of 40 kN, if the permissible stress is 150 MPa.​

Answer 1

The required diameter of the steel rod is 18.43 m.

Given:

Load = 40 KN
Stress = 150 MPa

To Find: Diameter

Solution:
Stress is extrasensory perception pursuing the whole extent of a material. The effect of stress on a carcass is chosen as strain. Stress can disfigure the crowd. How much force material happening maybe calculated utilizing stress wholes. Stress maybe classification into three classifications resting on upon the management of the deforming forces pursuing the party.

This restoring force will be equal in magnitude and opposite in direction to the applied deforming force

Let calculate it through formula:
Area = $\pi /4*d^2$

1 KN = 1000 N
Stress = Load/Area
$D^2 = 40000*14/150\pi$

$D^2 = 339.66$

D = 18.43

Hence the diameter is 18.43 metre.

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