Question

Find the rerm independent of x in the expansion of (x-1/x)^12​

Answer 1

Answer:

(x2+x1)12=E

rth term is independent of x

So E⇒12C0(x2)12+....12C1(x2)12−1(x1)1+...12C8(x2)12−8(x1)8+....12C12(x2)0(x1)12

So, 9th term ⇒12C8(x2)4(x1)8

⇒12C