Question

find the resipocal of the following rational number I। (-3\7)^-3 ÷( -3\7)^-4​

Answer 1

✧$\huge \mathcal \red {\underline{\underline{A}}}$ $\huge \mathcal \green {\underline{\underline{N}}}$ $\huge \mathcal \pink {\underline{\underline{S}}}$ $\huge \mathcal \blue {\underline{\underline{W}}}$ $\huge \mathcal \orange {\underline{\underline {E}}}$ $\huge \mathcal \purple {\underline{\underline{R}}}$✧

❥︎ Given :

$(\frac {-3}{7}) ^{-3} ÷ (\frac {-3}{7}) ^{-4}$

❥︎ To Find :

The reciprocal

❥︎ Solution :

$( \frac {-3}{7}) ^{-3} ÷ (\frac {-3}{7}) ^{-4}$

$(- \frac {7}{3}) ^{3} ÷ ( - \frac {7}{3}) ^{4}$

$= (- \frac {7}{3}) ^{3-4}$

$= (- \frac {7}{3}) ^{-1}$

$= (- \frac {3}{7}) ^{1}$

$= (- \frac {3}{7})$

➛ Reciprocal = $(- \frac {7}{3})$

$\implies$ Hence, the reciprocal of $\: (\frac {-3}{7}) ^{-3} ÷ (\frac {-3}{7}) ^{-4} \:$ is $\: (- \frac {7}{3}).$

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Answer 2

$( { \frac{ - 3}{7} })^{ - 3} \div ( { \frac{ - 3}{7} })^{ - 4}$

$( { \frac{7}{ - 3} })^{3} \div ( { \frac{7}{ - 3} })^{4}$

$\frac{343}{ - 27} \div \frac{2401}{ - 81}$

$\frac{343}{ - 27} \times \frac{ - 81}{2401}$

$= - \frac{3}{7} \: ans$

Or answer in picture