Find the resistance between A and B in the following network
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2 ohm
Two resistors are connected in series so
3 ohm + 3 ohm = 6 ohm
Now this 6 ohm resistor and 3 ohm resistor are in parallel
So 1\resistance of ab = 1\6 + 1\3
=2ohm
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Answer:
2ohm
Explanation:
since the resistors on arms ac and bc are connected in series,Rs = 3ohm + 3ohm = 6ohm . And this effective resistor is connected in parallel with the resistor of arm ab
therefore 1/Rp = 1/3 + 1/6
= 3/6
= 1/2
Rp = 2ohm
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