find the resistance effective from pq
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Answer:
1.2ohm
Explanation:
4 ohm and 6ohm are connected in series therefore R1+R2=4+6=10ohm
similarly,3ohm and 7ohm are connected in series therefore R1+ R2=7+3=10ohm
and the three are now connected in parallel
therefore 1/R1+1/R2+1/R3=1/10+1/10+1/1,
1/5+1=5+1/5=6/5=1.2ohm
(After finding two in series parallel diagram is shown in picture)
Hope it helps..........
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Answer:
10 /12
Explanation:
6 ohm and 4ohm are in series
so their equivalent resistance is 10ohm .
now , 10 ohm and 1ohm are in parllel.
so their equivalent resistance is 10 / 11 ohm .
7 and 3 ohm are in series. so their equivalent resistance is 10 ohm
finally 10 / 11 ohm & 10 ohm are in parllel.
so answer is 11 / 10 +1/10 .
1/R = 12/10
R = 10 /12
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