Question

Find the resistance of a bulb rated as 100W-250V.​

Answer 1

Answer:  $R = 625$ Ω

Explanation:

Given:

A bulb in which:

• Power = P = 100 W
• Potential Difference = V =250 V

To find:

The resistance of the bulb = R = ?

Proof:

We know that:

$P = \frac{V^2}{R}$

Substituting the values of P and V in the above equation, we get:

$= 100 =\frac{(250)^2}{R}$

⇒ $R = \frac{250 X 250 }{100}$

⇒ $R = 25 X 25$

⇒ $R = 625$ Ω

Hence, proved.

Hope you got that.

Thank You.