Question

find the resistance of a hollow cylindrical conductor of length 1.0 m with outer and inner radii 4.0mm and 1.0mm respectively .The resistivity of a material is 2.0×10_8 ohmsmeter
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Answer 1

Explanation:

hope it will help you bro

Answer 2

Explanation:

The area of cross section of hollow cylinder=A=π(R

2

−r

2

)

=π(4

2

−1

2

)×10

−6

m

2

The length of the cylinder=1m

Resistivity of material=ρ=2×10

−8

Ωm

Hence resistance=

A

ρl

=

π(4

2

−1

2

)×10

−6

2×10

−8

×1

=2.1×10

−3

Ω