Find the resistance of an ebonite rod of length 1m and area of cross section 2mm square.the resisitivity of ebonite is 10 Ray's to 16 ohm metre
Answers
Answered by
4
Answer:
we know that Resistance is given by R = ¶l/a
where ¶ is resistivity of the material
l is length of the wire .
a is area of cross section of the wire .
So R = 100×10^-6 × 1/2×10^-6
=> R = 50 ohm
Explanation:
we know that Resistance is given by R = ¶l/a
where ¶ is resistivity of the material
l is length of the wire .
a is area of cross section of the wire .
So R = 100×10^-6 × 1/2×10^-6
=> R = 50 ohm
Answered by
2
Answer:
50 ohm.
Explanation:
we know that,
R=p*L/A
where p is resistivity of wire.
L is length of wire
A is area of cross section
So,R=100*10^-6*1/2*10^-6
=50ohm
Similar questions