Question

find the resistance of bulb rates as 100 W -250W​

Answer 1

The rating 100W – 250 V on the bulb means that if the bulb is lighted on a 250V supply, it consumes 100W electrical power i.e., 100 electrical energy in 1 second.

Given : P = 100 W, V = 250 volt.

(i) The resistance of filament, R = V2/P = (250)2/100 = 625Ω

(ii) The current through the filament, I = P/V = 1000/250 = 4A

Answer 2

Answer:

193.6 to 484 ohm

please rate hope it helps

Explanation:

if you pick the regular house voltage 220V

then

P = V.V/R

then

R_1 = V^2 / P = 220^2/100 = 48400/100= 484 ohm

R_2 = V^2/P = 220^2/250 = 48400/250=193.6 ohm

then the resistance of the bulb will be in the range of

193.6-484 ohm