Find the resistance of eureka wire 1.1m long and 0.2mm in diameter. Resistivity of eureka=49x10^-8 OHM. What is the current flowing through the wire when a potential difference of 1V is applied across its ends?
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Answer:
length = 1.1m or 11/10m
area of crossection = 0.2mm = 1/500000msquare
resistivity= 49×10^-8ohm
therefore resistance = {(49×10^-8)×11/10}/1/500000
(49×10^-8×11)/10×5×10^5
(49×10^-8×11)/5×10^6
(539×10^-14)/5
=107.8×10^-14ohm
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