Question

find the resistance of the conductor when 2A of current flowing in a circuit which is connected to 120v battery​

Answer 1

Answer:

I am sorry I don't know‍♀

Answer 2

$\huge\color{orange}\boxed{\colorbox{yellow}{☞Answer♡}}$I

1

=2A,I

2

=0.5A

R

1

=2Ω,R

2

=9Ω

Supplied voltage is same.

To find,

Internal Resistance of battery,r=?

E=V+I⋅r

E=I⋅R+I⋅r

E=I⋅(R+r)

∴I=

(R+r)

E

E

1

=2⋅(2+r) and E

2

=0.5⋅(9+r)

As the supplied voltage is same,

So, E

1

=E

2

⇒2⋅(2+r)=0.5⋅(9+r)

⇒

0.5

2

=

2+r

9+r

⇒4=

2+r

9+r

⇒4⋅(2+r)=(9+r)

⇒8+4r=9+r

⇒4r−r=9−8

⇒3r=1

⇒r=

3

1

Ω

Therefore, Internal Resistance of battery is

3

to

1

Ω

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