Question

find the resistance of the following combinations
( please ans with steps)​

Answer 1

SoluTion:

(1). Here, 2nd and 3rd resistors are in parallel combination. ( Say P )

1/Rp = 1/1 + 1/1

→ 1/Rp = 2/1

→ Rp = 1/2 Ω

Similarly, 5th and 6th resistors are in parallel combination. ( Say Q )

1/Rp = 1/1 + 1/1

→ 1/Rp = 2/1

→ Rp = 1/2 Ω

Now, resistor 1, resistor 4, P and Q are in series combination.

Rs = 1 + 1/2 + 1/2 + 1

→ Rs = 3 Ω

Hence, total resistance of the given combination is 3 Ω.

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(2). Here, 1st and 2nd resistors are in parallel combination. (Say R)

1/Rp = 1/2 + 1/2

→ 1/Rp = 2/2

→ 1/Rp = 1

→ Rp = 1 Ω

Similarly, 3rd and 4th resistors are in parallel combination. (Say S)

1/Rp = 1/3 + 1/3

→ 1/Rp = 2/3

→ Rp = 3/2 Ω

Samj1 wase as, 5th and 6th resistors are in parallel combination too. (Say T)

1/Rp = 1/4 + 1/4

→ 1/Rp = 2/4

→ 1/Rp = 1/2

→ Rp = 2 Ωp

Now, R, S and T are in series combination.

Rs = 1 + 3/2 + 2

→ Rs = 4.5 Ω

Hence, total resistance of given combination is 4.5 Ω.