Find the resistance of the wire of length 20m needed to prepare a coil of resistance 30ohm (Resistivity of material of wire is 2.48×10^-7
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Answer:
Explanation:We know that
R=ρ
4
l
HEre, R=25Ω, ρ=3.142×10
−7
Ωm
A=πr
2
, l=25m
r is the radius of circular cross ectional of wire. So,
⇒ 25=(3.142×10
−7
)
(3.142)r
2
(25)
⇒ r
2
10
−7
⇒ r=10
−
2
7
=3.16×10
−3
m
Radius of cross section is 3.16mm
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