Question

Find the resistance when the potential difference is 6V & a charge of 3C passes thru it in 10 seconds

Answer 1

Answer:

v= 6

I = 3

R= V÷I

6÷ 3

= 2 ohm

Explanation:

As we know resistance equal to potential difference upon current therefore 6 ÷ 3 equal to

2 ohm

Answer 2

Required Answer :

Resistance = 20 Ω

Explication of steps :

As per the provided question, we have :

• Potential difference (V) = 6V
• Charge (Q) = 3C
• Time (t) = 10 s

We have to find the resistance (R).

According to Ohm's law,

$\longmapsto \boxed { \sf{ V = IR} }$

• V denotes potential difference
• I denotes current
• R denotes resistance

SI units :

• SI unit of p.d is volts (V).
• SI unit of current is Ampere (A).
• SI unit of resistance is Ohm (Ω).

Finding current (I) :

We know that,

$\longmapsto \boxed { \sf{ I = \dfrac{Q}{t} } }$

• I is current and its SI unit is Ampere (A).
• Q is charge and its SI unit is Coulomb (C).
• t is time and its SI unit is seconds (s).

Substituting values :

$\longmapsto \sf { I = \dfrac{3}{10} A }$

$\longmapsto \sf { I = 0.3 \: A }$ ★

Now, we have :

• Current passing (I) = 0.3 A
• Potential difference (V) = 6V

We know that,

$\longmapsto \boxed { \sf{ V = IR} }$

Substituting values,

$\longmapsto \sf { 6 = 0.3R }$

$\longmapsto \sf { \dfrac{6}{0.3} \Omega = R }$

$\longmapsto \sf { \dfrac{6 \times 10}{3} \Omega = R }$

$\longmapsto \sf { \dfrac{60}{3} \Omega = R }$

$\longmapsto \boxed{ \pmb{\sf \red{ 20 \Omega = R }}}$

Therefore, the resistance is 20 Ω.