find the resistant of the flood light bulbs of capacity of 1000 w when the current flowing is 2 ampere
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Answered by
1
Answer:
We know,
P=I^2R
R=P/I^2
=1000/2^2
=1000/4
=250 ohm
Answered by
0
Explanation:
250 ohm is the answer for the above question
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