Question

Find the resistivity of conductor of length 2m and diameter 1cm. Having a resistance of 5ohm

Answer 1

Explanation:

given,

R=5ohm

d=1cm=0.01

r=0.01/2

l=2m

now,

area=πr^2

=22/7×(0.01/2)×(0.01/2)

=0.0022/28m^2

now,

p(resistivity)=R×A/l

=5×0.0022/28×2

= 0.011/56

=0.0001964ohm m

=1.964×10^-4ohm m

may be math calculation going to mistake but process is right.you can try on notebook.

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