Find the resistor in which maximum heat will be produced
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Home >> JEEMAIN and NEET >> JEEMAIN-2014
The resistor in which maximum heat will be produced is

6Ω2Ω5Ω4Ω6Ω2Ω5Ω4Ω
jeemain
physics
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asked May 11, 2015 by meena.p

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Solution :
The potential drop across 3Ω,6Ω3Ω,6Ω and 2Ω2Ω resistors are same as parallel.
we also know Hα1RHα1R
So of these 2Ω2Ω resistor will generate more heat .
Similarly 5Ω5Ω and 4Ω4Ω are in parallel, so 4ω4ω resistor will generate more heat.
Now, the gives circuit equivalent to
V1V2=1209=920V1V2=1209=920
V1=(929)V1=(929)VV
V2=(2029)V2=(2029)VV
Power accross 2Ω2Ω resistor
P1=V212=(929)2V2P1=V122=(929)2V2
Power accross 4Ω4Ω resistor
P2=V224=(2029)2V4P2=V224=(2029)2V4
P2>P1P2>P1
These heat generated across 4Ω4Ω resistor is maximum
Answer : 6Ω
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Home >> JEEMAIN and NEET >> JEEMAIN-2014
The resistor in which maximum heat will be produced is

6Ω2Ω5Ω4Ω6Ω2Ω5Ω4Ω
jeemain
physics
question-paper-1
 Share
asked May 11, 2015 by meena.p

1 Answer
Solution :
The potential drop across 3Ω,6Ω3Ω,6Ω and 2Ω2Ω resistors are same as parallel.
we also know Hα1RHα1R
So of these 2Ω2Ω resistor will generate more heat .
Similarly 5Ω5Ω and 4Ω4Ω are in parallel, so 4ω4ω resistor will generate more heat.
Now, the gives circuit equivalent to
V1V2=1209=920V1V2=1209=920
V1=(929)V1=(929)VV
V2=(2029)V2=(2029)VV
Power accross 2Ω2Ω resistor
P1=V212=(929)2V2P1=V122=(929)2V2
Power accross 4Ω4Ω resistor
P2=V224=(2029)2V4P2=V224=(2029)2V4
P2>P1P2>P1
These heat generated across 4Ω4Ω resistor is maximum
Answer : 6Ω
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