Physics, asked by surajkumardba2005, 7 months ago

find the result of mixing 10 gram of ice at -10 degree Celsius with 10 gram of water at 10 degree Celsius is specific heat capacity of Ice 2.1 joule per gram Kelvin specific latent heat of ice is 336 joule per gram specific heat capacity of water is 4.2 joule per gram Kelvin​

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Answered by tanujakale62
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Answer:

result of mixing 10 gram of ice at -10 degree Celsius with 10 gram of water at 10 degree Celsius is specific heat capacity of Ice 2.1 joule per gram Kelvin specific latent heat of ice is 336 joule per gram specific heat capacity of water is 4.2 joule per gram Kelvin

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