Question

Find the result of mixing 10gm of
ice at -8°C with 10gm of water 12°C?
(Sp. heat of ice=0.5cal/gm°c, latent
heat of fusion of ice=80cal/gm)​

Answer 1

Answer:

J = 4.2 x 10 ' erg / cal ) S = 0.03 cal / gm / ° C ) 12. ... 10 gm of a metal at 100 ° C is immersed in a mixture of ice and water at 0 ° C ... at 100 ° C ? Specific heat of ice = 0.5 cal / gm / ° C , latent heat of ice = 80 cal ...

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Answer 2

ice at -8°C with 10gm of water 12°C?

(Sp. heat of ice=0.5cal/gm°c, latent

heat of fusion of ice=80cal/gm)