find the result of multiplying the sum of of all integers between 50 to 80 from the sum of all integers from 10 to 20
Answers
Answered by
1
Step-by-step explanation:
3x² - 2√6x + 2 = 0
We will factorise
Using splitting midterm theorem
3x² - √6x - √6x + 2 = 0
3x² - √2 × 3x - √ 2 × 3x + 2 = 0
3x² - ( √2 ) ( √3 )x - (√2)(√3)x + 2 = 0
3x² ( √3x - √2 ) - √2 ( √3x - √2 ) = 0
( √ 3x - √2 ) ( √3x - √ 2 ) = 0
√ 3x - √2 = 0
√3x = √2
x = √2 / √3
√3x - √2 = 0
\sqrt{ \frac{2}{3} }
3
2
√3x = √2
x = √2 / √ 3
Hence x =
\sqrt{ \frac{2}{3} }
3
2
Answered by
2
so adding all integers in between 50 to 80
sum becomes 1885
and finding the integers in between 10 to 20
sum becomes 135
PRODUCT OF 1885 AND 135 = 254475
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