Find the resultant amplitude and the phase difference between the resultant wave and the first wave , in the event the following waves interfere at a point , y_(1) = ( 3 cm) sin omega t, y_(2) = ( 4 cm) sin (omega t + (pi)/( 2)), y_(3) = ( 5 cm ) sin ( omega t + pi)
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1
Answer:
Explanation:
he resultant wave y=y
1
+y
2
y=3sinωt+4sin(ωt+π/3)
=3sinωt+2sinωt+2
3
cosωt
=5sinωt+2
3
cosωt
Amplitude of the resultant wave is given by =
(5)
2
+(2
3
)
2
=
25+12
=
37
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