Question

Find the resultant electric field due to an electric dipole of dipole moment 2aq, (2a being the separation between the charges ± q) at a point ‘x’ on its equator.

Answer 1

Answer:

Electric field due to dipole at its equatorial position is given as

$E = \frac{kP}{(x^2 + a^2)^{3/2}}$

Explanation:

As we know that dipole is the combination of two equal and opposite charges

here we have dipole moment given as

$P = q(2a)$

now let say a point exist at an equatorial distance "x"

So the electric field at that position is given as

$E_1 = \frac{kq}{x^2 + a^2}$

similarly electric field due to other end negative charge

$E_2 = \frac{kq}{x^2 + a^2}$

now vertical component of electric field will cancel out while horizontal components will add together

so we have

$E = E_1 cos\theta + E_2 cos\theta$

$E = 2(\frac{kq}{x^2 + a^2})cos\theta$

here we know that

$cos\theta = \frac{a}{\sqrt{x^2 + a^2}}$

$E = \frac{2kqa}{(x^2 + a^2)^{3/2}}$

so we have

$E = \frac{kP}{(x^2 + a^2)^{3/2}}$

#Learn

Topic : Electric field due to dipole

https://brainly.in/question/9694765