find the resultant magnetic field and direction at point O in given circle. there are 2 circle at cnetre o 2cm and 4m is given and at axial 4m and 2a is given.
Answers
Explanation:
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Answer:
We know Magnetic field at centre of a coil having Current I, radius r and number of turns N is given as B=
2r
μ
0
NI
and at a distance x from the centre and on the axis is B=
2(x
2
+r
2
)
μ
0
NIx
and its direction is given by right-hand screw rule i.e.
if the observer sees that the current is anticlockwise then the field will be towards the observer and vice-versa, as shown in the figure−1
Part a
Field at center O
1
will be difference of field due to loop-1 and loop-2
AtO
1
B
net
=
2r
μ
0
NI
-
2(x
2
+r
2
)
μ
0
NIx
towards observer
putting μ
0
=4π×10
−7
,N=6, r=.04 meter ,x= .06 meter and I = 1 all units in S.I. system
we get B
net
=5.07×10
−5
Tesla towards the observer
Similarly, AtO
1
the filed due to circle 2 will dominate so net filed will be
B
net
=5.07×10
−5
Tesla in a direction away from the observer.
Part b
According to the above theory the field at the midpoint on the axis of joining the centres will be equal and opposite as current in loops is opposite so net field is zero there at O
Explanation:
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