Question

Find the resultant of 3n and 4N at right angle

Answer 1

Answer:

The resultant of two forces 3N and 4N acting at right angles to each other will be 5N.

Explanation:

$|A+B| = \sqrt{A^2 + B^2 + 2AB Cos Theta}$

$Cos 90 = 0$

$|A+B| = \sqrt{A^2 + B^2}$

$|A+B| = \sqrt{9+16} = \sqrt{25} \\ |A+B| =5N$

Resultant = 5N