Question

Find the resultant of the following forces acting simuntaneosly at a point... 1-a force 50n along x axis ...2 a force of 40N at an anglr 60' ....3 a force of 60N acting at 330'

Answer 1

R = Resultant Force

Fy= Force at y

Fx= Force at x

R = Fx + Fy

Fx=50(?)

the Force in the x direction is given as 50 something.

the Force Resultant direction is 60 degrees from x axis

Fx=R cos(60)=50(?)

R = 50(?)/cos(60)

cos(60)=1/2

-——————————

R= 100(?)

_______________________

Fy=R sin(60)

sin (60)=square root of 3 / 2

Fy = 100 • square root of 3 / 2

-——————

Fy = 86.6(?)