Question

Find the resultant of the following two displacements: 2m at 30 deg at 4m at 120 deg. The angles are taken relative to the x-axis

Answer 1

Explanation:

Given Find the resultant of the following two displacements: 2 m at 30 deg at 4 m at 120 deg. The angles are taken relative to the x-axis

• Now we have two displacements that is  
• R1 = 2 cos 30 – 4 cos 60
•      = 2 x √3 / 2 – 4 x  1 / 2
•      =  √3 - 2
•      =  1.732 - 2
•     = - 0.268 m
• R2 = 2 sin 30 + 4 sin 60
•     = 2 x 1/2 + 4 x √3 / 2
•     = 1 + 2 √3
•    = 1 + 2 (1.732)
•    =  1 + 3.464
•     = 4.464 m
• Now R = √R 1^2 + R2^2
•             = √(-0.268)^2 + (4.464)^2
•              = √0.0718 + 19.927
•               = √19.999
•               = 4.472 m
• Now tan Q = R 2 / R1
•                     = 4.464 / - 0.268
•                       = - 16.656
•            Or Q = - 86.6 degree
• Now resultant will be 180 – 86.6 = 93.4 degree

Reference link will be

https://brainly.in/question/15142358