Question

find the resultant of the force F1 and F2 where F1 is equal to 10 Newton F2 is equal to 10 Newton and theta is equal to 60 degree​

Answer 1

F1 = 10N

F2 = 10N

∅ = 60°

Resultant vector =

$\sqrt{a {}^{2} + b {}^{2} + 2abcos60 }$

$\sqrt{10 {}^{2} + 10 {}^{2} + 2 \times 10 \times 10 \times cos60 }$

$\sqrt{100 + 100 + 200 \times \frac{1}{2} }$

$\sqrt{100 + 100 + 100}$

$\sqrt{300}$

Resultant force = 10√3N

Cheers!

Answer 2

At 60 degrees inclination, general formula for providing resultant force of forces of equal magnitude is

R=sqrt.(3)×F1

Resultant force =10×sqrt.(3)

As sqrt.(3)=1.732(nearly)

Resultant Force=17.32N (approximately)