Question

find the resultant of two force one 6N due east and the other 8N due north

Answer 1

HEYA!!
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⏪THE Resultant R of two forces is given by ,


$r \: = \sqrt{a {}^{2} + b {}^{2} + 2ab \: \: cos \alpha }$
Here A = 6 N

B = 8 N

Also Cos@ = 90° since they are perpendicular.


We have

R = √ ( 6 )^2 + ( 8 )^2 + 2 × 6 × 8 × 0

R = √ 100

Hence resultant is 10N.

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Answer 2

Answer:

Resultant is 10N.

Explanation :- r \: = \sqrt{a {}^{2} + b {}^{2} + 2ab \: \: cos \alpha } \\ \\ \\

Here A = 6 N

B = 8 N

Also Cos@ = 90° since they are perpendicular.

We have

R = √ ( 6 )^2 + ( 8 )^2 + 2 × 6 × 8 × 0

R = √ 100.

you have understood