find the resultant of two forces one is 6 newton due east and other 8 newton due north
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resultant between two forces is √A^2+B^2+2ABcos¤ ,where ¤ is angle between the vectors.
angle in this case is 90° and we know that cos90° is 0 hence the and is √A^2+B^2 which is √36+64=√100=10.
angle in this case is 90° and we know that cos90° is 0 hence the and is √A^2+B^2 which is √36+64=√100=10.
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Resultant will be 10
8^2+6^2=64 +36 =100
100is square root of 10
8^2+6^2=64 +36 =100
100is square root of 10
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