find the resultant resistance between p and q.
plz give explanation
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7 and 3 are in series so equivalent resistance is equal to 10
6 and 4 are in series so equivalent resistance is equal to 10
1 and 10 and 10 are in parallel so equivalent resistance will be equal to 5÷6
ans:5÷6
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Hi !!
First of all upper part of PQ take in series and ad them , so , 7+3 z,= 10ohm
Then , similarly , lower part of PQ add them in series so, 6+4 = 10ohm
Now, add those three resister in parallel them
we get , 1/Requavalent = 1/10+1/1+1/10 = 12/10
Since, R = 10/12 = 5/6 Answer
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