find the resulting inequation when
i- 10 is added to each side of 4x-3<2
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Answer:
4x-3+i-10<2+i-10
Therefore, 4x-13+i<i-8
adding 8 on bothsides
Therefore, 4x-5+i<i
subtracting i on bothsides,
Therefore , 4x-5<0-ANS
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