Question

find the resultint of 2 vectors of 30 n and 40n acting at a point of 0 at an angle of 60 each other​

Answer 1

Step-by-step explanation:

We know, the resultant R is given by:

$r = \sqrt{{p}^{2} +{q}^{2} + 2pqcos \alpha }$

Where, Alpha is the angle between the two vectors.

So, R can be calculated as follows:

$r = \sqrt{ {30}^{2} + {40}^{2} + 2 \times 30 \times 40 \times cos60 } \\ r = \sqrt{900 + 1600 + 2400 \times \frac{1}{2}} \\ r = \sqrt{3700} \\ r = 60.82$

Hence magnitude of the resultant of the vectors = 60.82 N

Answer 2

ANSWER....

Q.1 WHAT IS VECTOR?

WE KNOW THAT THERE ARE TWO TYPE OF QUANTITY ONE IS SCALAR AND OTHER IS VECTOR SO WE CAN'T ADD BOTH THE QUANTITY IN SIMILAR WAY BECAUSE SCALAR HAS MAGNITUDE BUT VECTOR HAS MAGNITUDE AND BOTH DIRECTION...

$let \: a \: and \: b \: are \: the \: two \: vector \: \\ with \: \alpha \: angle \: between \: them \\ \\ so \: resultant \: of \: both \: vector \: will \: be \\ \\ r= \sqrt{ {a}^{2} + {b}^{2} + 2ab \cos \alpha } \\ \\ acc \: to \: your \: question..... \\ \\ a = 30 \\ b = 40 \\ \alpha = 60 \\ \\ r = \sqrt{ {30}^{2} + {40}^{2} + 2(30)(40) \cos60 } \\ \\ r = \sqrt{900 + 1600 + 1200} \\ \\ r = \sqrt{3700} \\ \\ r = 10 \times 6.082 \\ \\ r = 60.82$

#BTSKINGDOM