Find the rightmost non zero digit of number (30)^2720
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Answered by
2
Hey here's your answer....
(30)^2720, we can write it as[(30)^4]^680
Or,[(10*3)^4]^680
The right most non-zero digit depends on the unit digit of [(3)^4]^680.
Unit digit of [(3)^4]^680,
Or, (81)^680
The unit digit of 81 is 1 so any power of 81 will always give its unit digit as 1.
Thus, required unit digit is 1.
Hope it helps you....
(30)^2720, we can write it as[(30)^4]^680
Or,[(10*3)^4]^680
The right most non-zero digit depends on the unit digit of [(3)^4]^680.
Unit digit of [(3)^4]^680,
Or, (81)^680
The unit digit of 81 is 1 so any power of 81 will always give its unit digit as 1.
Thus, required unit digit is 1.
Hope it helps you....
Nereida:
Pls mark brainliest
Answered by
0
Right most nonzero digit in
30^1 = 3
30^2 = 9
30^3= 7
30^4 = 1
30^5= 3
and the pattern 3,9,7,1) repeats
Now 30^2720 = 30^ 4(680)
= Last digit of 30^2720 = 1
30^1 = 3
30^2 = 9
30^3= 7
30^4 = 1
30^5= 3
and the pattern 3,9,7,1) repeats
Now 30^2720 = 30^ 4(680)
= Last digit of 30^2720 = 1
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