Question

Find the rms speed of argon molecule at 27°C (Molecular weight of argon = 40 gm/mol)
(A) 234 2 m/s
(B) 342.2 m/s
(C) 432 2 m/s
(D) 243 2 m/s​

Answer 1

Explanation:

a ans is right OK

stay home stay safe

Answer 2

Answer:

432.2m/s

Explanation:

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expression

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu=

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M3RT

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M3RTu=

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M3RTu= 40×10

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M3RTu= 40×10 −3

The rms speed (u) is related to the temperature (T) and molecular weight (M) by the expressionu= M3RTu= 40×10 −3 kg/mol

under root 3×8.314J/molK×(27+273.15)K

3×8.314J/molK×(27+273.15)Ku=432.2m/s

3×8.314J/molK×(27+273.15)Ku=432.2m/sHence, the rms speed is 432.2 m/s

MARK ME AS A BRAINLIST