Question

find the RMS value velocity of molecules of hydrogen at 20°c molecular weight of hydrogen is 2 and R = 8.31×10 ki power 3 J/(kilo mole degree)​

Answer 1

Answer:

• 1911.08 m/s is the required answer.

Explanation:

According to the Question

It is given that,

• Molecular weight of hydrogen,M = 2
• Gas Constant ,R = 8.31 × 10³
• Temperature ,T = 20°C

Firstly we convert the unit here ,

Conversion of Unit

→ T = 273 + 20

→ T = 293K

Now, calculating the RMS value of molecules of hydrogen .

$\\ \star{\boxed{\purple{\bf \bold{V_{rms} = \sqrt{ \frac{3RT}{M}}}}}}$

On substituting the value we get

$\implies \sf \: V_{rms} \: = \sqrt{ \frac{3 \times 8.31 \times 10 {}^{ 3} \times 293 }{2} } \\ \\ \implies \sf \: V_{rms} \: = \sqrt{ \frac{3 \times 8.31 \times 10^{3} \times 293}{2} } \\ \\ \\ \implies \sf \: V_{rms} \: = \sqrt{ \frac{7304490}{2 } } \\ \\ \\ \implies \sf \: V_{rms} \: = \sqrt{3652245} \\ \\ \\ \implies \sf \: V_{rms} \: = 1911.08\: ms {}^{ - 1}$

• Hence, the Vrms velocity of the given molecules are 1911.08m/s

Answer 2

$\large{\mathfrak{\red{\underbrace{\overbrace{\purple{\boxed{\blue{★Answer★}}}}}}}}$

It is given that,

Molecular weight of hydrogen, M = 2

Gas Constant ,R = 8.31 × 10³

Temperature,T = 20°C

Conversion of Unit:

= T = 273 + 20

= T = 293K

Calculate the RMS value of molecules of hydrogen.

$vrms = \sqrt{\frac{3rt}{m} }$

On substituting the value we get

Vrms =

$\sqrt{ \frac{3 \times 8.31 \times 10 {}^{3} \times 293}{2} }$

Vrms =

$\sqrt{ \frac{7304490}{2} }$

Vrms=

$\sqrt{ \frac{365225}{} }$

Vrms =

$1911.08ms {}^{ - 1}$

:: So the answer is 1911.08m/s

$\large{\mathfrak{\red{\underbrace{\overbrace{\purple{\boxed{\blue{★1911.08m/s★}}}}}}}}$