Question

find the rods of the given equation
equation 2x²_ 3x+1.​

Answer 1

Answer:

$2 {x}^{2} - 3x + 1 = 0 \\ \\ 2 {x}^{2} - 2x - x + 1 = 0 \\ \\ 2x(x - 1) - 1(x - 1) = 0 \\ \\ (x - 1) \: (2x - 1) = 0 \\ \\ x = 1 \: \: or \: \: \: x = \frac{1}{2}$

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Answer 2

Answer:

HEY DEAR

HERE IS UR ANSWER

$</p><p>2x2−3x+1=0</p><p>2x2−2x−x+1=0</p><p>2x(x−1)−1(x−1)=0</p><p>(x−1)(2x−1)=0</p><p>x=1</p><p>or</p><p>x=21</p><p>$

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