find the root (4x²-9x- 9x +2
Answers
Answer:
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Step-by-step explanation:
Step by step solution :
STEP
1
:
Equation at the end of step 1
((0 - 22x2) - 9x) - 2 = 0
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-4x2 - 9x - 2 = -1 • (4x2 + 9x + 2)
Trying to factor by splitting the middle term
3.2 Factoring 4x2 + 9x + 2
The first term is, 4x2 its coefficient is 4 .
The middle term is, +9x its coefficient is 9 .
The last term, "the constant", is +2
Step-1 : Multiply the coefficient of the first term by the constant 4 • 2 = 8
Step-2 : Find two factors of 8 whose sum equals the coefficient of the middle term, which is 9 .
-8 + -1 = -9
-4 + -2 = -6
-2 + -4 = -6
-1 + -8 = -9
1 + 8 = 9 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 8
4x2 + 1x + 8x + 2
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (4x+1)
Add up the last 2 terms, pulling out common factors :
2 • (4x+1)
Step-5 : Add up the four terms of step 4 :
(x+2) • (4x+1)
Which is the desired factorization