Question

find the root by completing square method 3x^-4√3x+4=0​

Answer 1

$3 {x}^{2} - 4 \sqrt{3} x + 4 = 0$

Multiplying both sides by 3

We get,

$9 {x}^{2} - 12 \sqrt{3} x + 12 = 0 \\ = > {(3x)}^{2} - (2 \times 3x \times 2 \sqrt{3} ) + {(2 \sqrt{3)} }^{2} - {(2 \sqrt{3)} }^{2} + 12 = 0 \\ = > {(3x - 2 \sqrt{3} )}^{2} - 12 + 12 = 0 \\ = > {(3x - 2 \sqrt{3} )}^{2} = 0 \\ = > 3x - 2 \sqrt{3} = 0 \\ = > x = \frac{2 \sqrt{3} }{3}$