Question

find the root by factorisation method x²+2 root 2x-6=0​

Answer 1

Answer:

$by \: factorisation \: method \: \: \: \\ \\ x = \sqrt{2} \: \: \: \: \: \: or \: \: \: \: \: x = - 3 \sqrt{2} .$

Step-by-step explanation:

GIVEN :

${x}^{2} + 2 \sqrt{2} x - 6 = 0$

TO FIND :

ROOTS OF THE GIVEN EQUATION BY FACTORISATION METHOD.

SOLUTION :

${x}^{2} + 2 \sqrt{2} x - 6 = 0 \\ \\ {x}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 6 = 0 \\ \\ x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) = 0 \\ \\ (x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0 \\ \\ then \: \: \: \: \: x = \sqrt{2} \: \: \: \: \: \: or \: \: \: \: \: x = - 3 \sqrt{2} .$