Question

find the root by factorization method:
x^2-2x+1=0​

Answer 1

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

So the given expression is 2x^2-x+1/8

Now multiply both LHS and RHS by 8

We get,

16x^2-8x+1=0

=>16x^2-4x-4x+1=0

=>4x(4x-1)-1(4x-1)=0

=>(4x-1)(4x-1)=0

=>(4x-1)^2=0

Hence the zeroes of the polynomial are x=1/4,1/4

Hope it helps you and please mark as the brainliest :)

Answer 2

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