Find the root by the method of completing square:
![5 {x}^{2} - 6x - 2 = 0 5 {x}^{2} - 6x - 2 = 0](https://tex.z-dn.net/?f=5+%7Bx%7D%5E%7B2%7D++-+6x+-+2+%3D+0)
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Answered by
2
Answer:
Step-by-step explanation:
5x^2 -6x -2 = 0
x^2 -(6/5)x -(2/5) = 0
(x)^2 - [2.(3/5).x] + (3/5)^2 - (3/5)^2 -(2/5) = 0
[x-(3/5)]^2 = (2/5)+(9/25)
[x-(3/5)]^2 = (19/25)
x-(3/5) = √19/5
x = (3/5) ± √19/5
Roots of the equation are
x = [3+(√19)]/5
& x = [3-(√19)]/5
Answered by
1
HLW BRO!
THE solution of YOUR QUESTION with completing square method is given below:
5X^2-6X-2=0
:DIVIDE it with 5
THEN,X^2-6X/5-2/5=0
adding 9/25 both side
:X^2-6X+9/25=2/5+9/25
:(X-3/5)^2=19/25
X-3/5=root 19/5
X=(3+root 19)/5 and (3-root19)/5
THANK U☺
THE solution of YOUR QUESTION with completing square method is given below:
5X^2-6X-2=0
:DIVIDE it with 5
THEN,X^2-6X/5-2/5=0
adding 9/25 both side
:X^2-6X+9/25=2/5+9/25
:(X-3/5)^2=19/25
X-3/5=root 19/5
X=(3+root 19)/5 and (3-root19)/5
THANK U☺
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