Question

find the root of (1/x-2)+(1/x)=8/(2x+5);x≠0,2,-5/2​

Answer 1

Answer:

x=5,1/2

Step-by-step explanation:

solution :

1/(x-2) +1/x =8/(2x+5)

or, (x+x-2)/x*(x-2)=8/(2x+5)

or, (2x-2)/(x²-2x)=8/(2x+5)

or, 2(x-1)/(x²-2x)=8/(2x+5)

or, (2x+5)*(x-1)=4(x²-2x)

or, 2x²-2x+5x-5=4x²-8x

or, 2x²-11x+5=0

or, 2x²-10x-x+5=0

or, 2x(x-5)-1(x-5)=0

or, (x-5)(2x-1)=0

or, x-5=0,2x-1=0

or, x=5,2x=1

or, x=5,x=1/2 (ans