Question

find the root of 2(3a+1)=12+2(4a+3)

Answer 1

Solution is attached below in image hope it helps you

Answer 2

Simplifying 2(3a + 1) = 12 + 2(4a + 3)
Reorder the terms: 2(1 + 3a) = 12 + 2(4a + 3)
(1 * 2 + 3a * 2) = 12 + 2(4a + 3)
 (2 + 6a) = 12 + 2(4a + 3)

Reorder the terms: 2 + 6a = 12 + 2(3 + 4a)
 2 + 6a = 12 + (3 * 2 + 4a * 2)
 2 + 6a = 12 + (6 + 8a)
Combine like terms: 12 + 6 = 18
2 + 6a = 18 + 8a
 Solving 2 + 6a = 18 + 8a
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right. Add '-8a' to each side of the equation.
 2 + 6a + -8a = 18 + 8a + -8a
 Combine like terms: 6a + -8a = -2a 2 + -2a = 18 + 8a + -8a
Combine like terms: 8a + -8a = 0 2 + -2a = 18 + 0 2 + -2a = 18
Add '-2' to each side of the equation.
 2 + -2 + -2a = 18 + -2
Combine like terms: 2 + -2 = 0 0 + -2a = 18 + -2 -2a = 18 + -2
 Combine like terms: 18 + -2 = 16 -2a = 16
Divide each side by '-2'. a = -8
Simplifying a = -8