find the root of 2x^2-32=0
Answers
Answered by
1
Answer:
4 or -4 is the root of this question
Answered by
2
Answer:
4 and -4
Step-by-step explanation:
2x² - 32 = 0
=> 2(x² - 16) = 0
=> x² - 16 = 0/2
=> x² - 4² = 0
=> (x-4) (x+4) = 0
=> x-4 =0 or x+4 =0
=> x = 4 or x = -4
Hence the roots of the given equation are 4 and -4.
MARK AS BRAINLIEST
Similar questions