Question

find the root of 2x^2-32=0​

Answer 1

Answer:

4 or -4 is the root of this question

Answer 2

Answer:

4 and -4

Step-by-step explanation:

2x² - 32 = 0

=> 2(x² - 16) = 0

=> x² - 16 = 0/2

=> x² - 4² = 0

=> (x-4) (x+4) = 0

=> x-4 =0 or x+4 =0

=> x = 4 or x = -4

Hence the roots of the given equation are 4 and -4.

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